x=1/8(y-2)^2

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Solution for x=1/8(y-2)^2 equation: 


x in (-oo:+oo)

x = (1/8)*(y-2)^2 // - (1/8)*(y-2)^2

x-((1/8)*(y-2)^2) = 0

(-1/8)*(y-2)^2+x = 0

x-1/8*(y-2)^2 = 0

x-1/8*(y-2)^2 = 0

x-1/8*y^2+1/2*y-1/2 = 0

x-1/8*y^2+1/2*y-1/2 = 0

x-1/8*y^2+1/2*y-1/2 = 0 // - 1/2*y-1/8*y^2-1/2

x = -(1/2*y-1/8*y^2-1/2)

x = 1/2-(-1/8*y^2)-(1/2*y)

x = 1/2-(-1/8*y^2)-(1/2*y)

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